NiF₆ Complexes: Diamagnetic or Paramagnetic? Hybridization States Explained

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SUMMARY

The discussion centers on the magnetic properties and hybridization states of the nickel fluoride complexes [NiF₆]²⁻ and [NiF₆]⁴⁻. It is established that [NiF₆]⁴⁻ is diamagnetic due to the absence of unpaired electrons, while [NiF₆]²⁻ is paramagnetic with unpaired electrons present. The hybridization state for both complexes is confirmed as sp³d², consistent with their octahedral geometry and the influence of fluoride as a weak field ligand.

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  • Understanding of coordination chemistry
  • Knowledge of ligand field theory
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  • Basic principles of magnetism in transition metal complexes
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  • Study the differences between strong and weak field ligands
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Chemistry students, particularly those studying coordination compounds, inorganic chemists, and anyone interested in the magnetic properties of transition metal complexes.

Suraj M
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Homework Statement


Could anyone tell me if [NiF₆]2- and [NiF₆]4- are diamagnetic or paramagnetic?
And also their hybridization states? please?

Homework Equations

The Attempt at a Solution


well i thought F is a weak ligand and hence a high spin complex formed, but i read a few places where it says that [NiF₆]4- is diamagnetic, which doesn't make sense to me. And i think the hybridization should be sp³d² but if its diamagnetic then i don't know what to do :-( could you please help me out?
thank you
 
nothing more i can add...
could someone please help me out here?please?
could you at least point me in the right direction?
 

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