No. of quadrilaterals in a polygon

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SUMMARY

The number of quadrilaterals that can be formed using the vertices of a convex polygon with 24 sides, where at least one side of the quadrilateral is common with the polygon, is calculated by subtracting the number of quadrilaterals with no sides in common from the total number of quadrilaterals. The total number of quadrilaterals is given by 24C4, which equals 10626. The number of quadrilaterals with no sides in common is calculated as 12C4, resulting in 495. Therefore, the final answer is 10626 - 495 = 10131.

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Homework Statement



Quadrilaterals are formed by using the vertices of a convex polygon of 24 sides. The number of quadrilaterals having atleast one side of the quadrilateral in common with the side of the polygon is ?


The Attempt at a Solution



We can find out the total no. of quadrilaterals that can be formed and subtract from it the no. of quadrilaterals with no side common to that of the polygon.

24C4 - 12C4 = 10131

I got 12 by choosing alternate vertices.
I don't get the correct answer this way :|
 
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I'm guessing here but what about 22C2 per side. You use 2 vertices for one side then you need 2 more to form the rest of the quadrilateral.
 

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