No problem, glad I could help!

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Kinematics -- Vector DE

Homework Statement


Printed homework problem 1 on a particle of mass m under gravity and air resistance proportional to the cube of its speed, with parts (a), (b) and (c) asking for the governing vector equation, the velocity with gravity neglected, and the velocity and position with air resistance neglected.


The Attempt at a Solution


Here's their solution.

Handwritten solution with parts (a) and (b): N2L gives sum F = d/dt p = m dv/dt, leading to m dv/dt = -mg z-hat - a(v dot v)v; part (b) manipulates v dot m dv/dt = -a(v dot v)^2 through to v = u(1 + 2av^2 t/m)^(-1/2).


I'm stuck on (b). The first and second lines are fine. But how do they get from the second line to the third line? And then in the fourth line, why are they integrating from u^2 to v^2?

EDIT: Sorry for the image size.
 
Chestermiller said:
They make the substitution v2 = x.

Chet

That's it?! I thought x denoted position (as a function of time)! Was losing my mind over this. Thanks.