Non-Abelian Group: (ab)^2 = (b^2)(a^2)?

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Homework Help Overview

The discussion revolves around properties of non-Abelian groups, specifically examining the expression \((ab)^2\) and its relation to \((b^2)(a^2)\). Participants explore the implications of non-commutativity in group operations.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss expanding the expression \((ab)^2\) and consider examples from the smallest non-Abelian group, \(S_3\). Questions arise regarding the inversion of elements and the order of multiplication in non-Abelian groups.

Discussion Status

The discussion is active, with participants providing insights into the properties of inverses in non-Abelian groups. Some guidance has been offered regarding the expansion of expressions and the nature of inverses, but no consensus has been reached on the original question.

Contextual Notes

Participants are exploring the implications of group properties without the constraints of formal homework, allowing for a more open-ended discussion.

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in a non abelian group does (ab)^2 = (b^2)(a^2)?
this isn't homework, my semester is over.
 
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1. Just expand (ab)^2

2. Or look in the smallest non abelian group there is: S_3
 
it expands to abab , but how come (ab)^-1 = (b^-1)(a^-1)?
 
because inversion reverses the order of the elements, it is an anti-automorphism and has nothing to do with the commutativity or otherwise of the group.

we know the inverse of ab is a c such that abc=1, bc=a^{-1}, and then c=b^{-1}a^{-1}
 
ok, thanks.
 
math-chick_41 said:
it expands to abab , but how come (ab)^-1 = (b^-1)(a^-1)?

What do you get if you multiply (ab)(b-1a-1)?
 

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