Non-diagonality of Dirac's Hamiltonian

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SUMMARY

The discussion centers on the non-diagonality of Dirac's Hamiltonian, specifically addressing the implications of gamma matrices not being diagonal. It is established that while momentum and spin are part of the complete set of commuting variables, the non-diagonal nature of the Hamiltonian leads to a change in the state of a particle with definite momentum and spin over time. The spin vector operator does not commute with the Hamiltonian, indicating that it is not a constant of motion, which is a critical point often overlooked in textbooks.

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  • Understanding of Dirac's Hamiltonian and its formulation
  • Familiarity with gamma matrices and their properties
  • Knowledge of quantum mechanics concepts such as eigenstates and commuting operators
  • Basic grasp of spin and momentum in quantum systems
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This discussion is beneficial for quantum physicists, students of quantum mechanics, and researchers focusing on relativistic quantum theories and the implications of non-diagonal Hamiltonians.

Mesmerized
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Hi all,

My question is why Dirac's Hamiltonian isn't diagonal? As much as I understand, the momentum of the particle and it's spin belong to the complete set of commuting variables, which define the state of the particle, and their eigenstates must also be energy eigenstates. But because Hamiltonian is non-diagonal (because gamma matrices are not diagonal), it follows that if we have a particle with definite momentum and definite spin, with time it is going to change it's state to become a particle with no definite spin.

Where am I wrong?
 
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The spin vector operator is no constant of motion (doesn't commute with the Hamiltonian, which is time-independent) for the Dirac' Hamiltonian, but [tex]\vec{S} \cdot \vec{P}[/tex] is.
 
thanks, don't know why it's not written in the textbook, and I made a wrong assumption
 

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