Non Geodesic Motion: Definition & Explanation

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Non-geodesic motion refers to movement that does not follow a geodesic, which is the path taken by objects under no external forces, excluding gravity. In general relativity, the world line of a non-spinning test particle is a geodesic, characterized by zero path curvature. Non-geodesic motion occurs when external forces, such as Lorentz forces acting on charged particles, affect the particle's trajectory, resulting in measurable path curvature. Spinning particles can deviate from geodesic paths due to spin-spin forces, although these effects are typically negligible in practical scenarios. Understanding these concepts is crucial for exploring the dynamics of particles in gravitational fields and electromagnetic contexts.
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What is non geodesic motion?
 
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Obvious definition- motion that does not follow a geodesic! In relativity, geodesics are the paths followed by objects with no "outside" forces acting on them (gravity not being considered an "outside" force here) so non-geodesic motion is motion with no outside forces.
 
Just to elaborate quickly on what HallsofIvy said: in general relativity, the world line of a (nonspinning) test particle is a geodesic, i.e. a curve with zero path curvature. More generally, the path curvature at any event on some world line is just the magnitude of acceleration experienced by the corresponding particle. For example, a charged particle in an "electrovacuum solution" of the Einstein field equation (EFE) will experience a nonzero Lorentz force, whose magnitude (at each event on the world line of the particle) agrees with the path curvature.
 
HallsofIvy said:
non-geodesic motion is motion with no outside forces.
I'm guessing you meant either "geodesic motion is motion with no outside forces" or else "non-geodesic motion is motion with outside forces"?
 
Good catch, JesseM, I missed that! But I am sure HallsofIvy simply mistyped.
 
Chris Hillman said:
Just to elaborate quickly on what HallsofIvy said: in general relativity, the world line of a (nonspinning) test particle is a geodesic, i.e. a curve with zero path curvature. More generally, the path curvature at any event on some world line is just the magnitude of acceleration experienced by the corresponding particle. For example, a charged particle in an "electrovacuum solution" of the Einstein field equation (EFE) will experience a nonzero Lorentz force, whose magnitude (at each event on the world line of the particle) agrees with the path curvature.

Why spinning particles don't have a geodesic path?
 
Spin-spin forces plus an essential PF link

emanaly said:
Why spinning particles don't have a geodesic path?

I didn't quite say that. However, in gtr, a spinning object immersed in a nonzero gravitational field (perhaps caused by a much larger nearby and spinning object) will in general experience a tiny "spin-spin" force and thus will be pushed off a geodesic path. However, these forces would be much too small to measure in any currently envisioned solar system experiments (at least, not any I know of). See for example "Dixon-Papapetrou equations" in Stephani, General relativity.

By the way, I urge all members to carefully read https://www.physicsforums.com/showthread.php?t=5374 if they have not already done so, and indeed to bookmark it for future reference.
 

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