Undergrad Nontrivial Normal Subgroup in Finite Groups with Index Constraints?

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The discussion revolves around a problem of group theory concerning finite groups and subgroups. It states that for a finite group G with a subgroup H of index n, if the order of G does not divide n!, then H must contain a nontrivial normal subgroup of G. The problem remains unanswered by participants, indicating a lack of engagement or understanding of the topic. A solution is provided by the original poster, suggesting that the problem is solvable but may require advanced knowledge in group theory. The thread highlights the complexities of subgroup structures in finite groups.
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Here is this week's POTW:

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Let $G$ be a finite group, and let $H$ be a subgroup of $G$ of index $n$. Prove that if the order of $G$ does not divide $n!$, then $H$ contains a nontrivial normal subgroup of $G$.

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No one answered this week's problem. You can read my solution below.

Let $G$ act on the set of left cosets of $H$ by left multiplication, and let $K$ be the kernel of the induced permutation representation. Then $K$ is the intersection of all conjugates of $H$, so $K$ is a normal subgroup of $G$ contained in $H$. Since $H$ has index $n$, $K$ has index dividing $n!$. Using the fact that $n!$ is not divisible by $|G|$, $K$ must be nontrivial.
 

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