- #1
Shawj02
- 20
- 0
Ok, the question says
Binomial with n=40. p=0.6 use normal approximation and determine..
a) value at 14.
b)value lest then 12.
So I thought I had this down and packed but the answer in the back of the book tells me otherwise. Anyways the following is my working.
Y~Nor(13.5<x<14.5)
Mean=np=24
S.D = sqrt(np(1-p)) = 3.094
larger prob area
Z=(x-mean)/S.D
=(14.5 - 24)/3.094
=-3.07
(Tables book, 3.07 = 0.9989)
So (1-0.9989)
smaller prob area
Z=(x-mean)/S.D
=(13.5 - 24)/3.094
=-3.39
(Tables book, 3.39 = 0.9997)
So (1-0.9997)
So the final answer is:
larger prob area - smaller prob area
total prob =(1-0.9989) - (1-0.9997)
=8*10^-4
But the actual answer is meant to be 0.049?
B) I do pretty much the same thing But after the whole Z=(x-mean)/S.D (x=11.5)
end up with Z=-4.034 Which isn't on the tables book. So I can't figgure out the final prob.
Thanks!
Binomial with n=40. p=0.6 use normal approximation and determine..
a) value at 14.
b)value lest then 12.
So I thought I had this down and packed but the answer in the back of the book tells me otherwise. Anyways the following is my working.
Y~Nor(13.5<x<14.5)
Mean=np=24
S.D = sqrt(np(1-p)) = 3.094
larger prob area
Z=(x-mean)/S.D
=(14.5 - 24)/3.094
=-3.07
(Tables book, 3.07 = 0.9989)
So (1-0.9989)
smaller prob area
Z=(x-mean)/S.D
=(13.5 - 24)/3.094
=-3.39
(Tables book, 3.39 = 0.9997)
So (1-0.9997)
So the final answer is:
larger prob area - smaller prob area
total prob =(1-0.9989) - (1-0.9997)
=8*10^-4
But the actual answer is meant to be 0.049?
B) I do pretty much the same thing But after the whole Z=(x-mean)/S.D (x=11.5)
end up with Z=-4.034 Which isn't on the tables book. So I can't figgure out the final prob.
Thanks!