Number of independent subcubes of a hypercube

  • Context: Graduate 
  • Thread starter Thread starter twoflower
  • Start date Start date
  • Tags Tags
    Independent
Click For Summary
SUMMARY

The discussion focuses on calculating the maximum number of independent subcubes within an n-dimensional hypercube, given m specific vertices. The solution requires analyzing the positions of these vertices across the (n-1)-dimensional faces of the hypercube. It is essential to account for overlapping vertices on adjacent faces to avoid double-counting the hypercubes formed. The approach involves an inductive calculation of hypercubes on each (n-r) dimensional face, where r represents the dimension reduction.

PREREQUISITES
  • Understanding of n-dimensional hypercubes
  • Knowledge of combinatorial geometry
  • Familiarity with inductive reasoning in mathematics
  • Basic concepts of vertex adjacency in geometric structures
NEXT STEPS
  • Study the properties of n-dimensional hypercubes and their faces
  • Learn about combinatorial counting techniques in geometry
  • Explore inductive proofs and their applications in higher dimensions
  • Investigate algorithms for calculating vertex adjacency in geometric shapes
USEFUL FOR

Mathematicians, computer scientists, and researchers in combinatorial geometry seeking to understand hypercube properties and subcube independence.

twoflower
Messages
363
Reaction score
0
Number of "independent" subcubes of a hypercube

Hello, I am trying to solve this problem: I have an n-dimensional hypercube and m of its vertices. Now I want to compute the maximum number of subcubes of the entire hypercube such that:
- each subcube from the set may contain only those m vertices
- no subcube from the set is part of another subcube from the set

Does anybody have any idea?

Thank you very much.


Standa
 
Physics news on Phys.org


I take the 'subcubes' to be hypercubes of lower dimension.
The answer depends on the positions of the m vertices critically. For each (n-1)dimensional face , find the number of vertices on it. If two adjacent faces contain 2 or more vertices, subtract the number of hypercubes on the common 'edge'. Inductively, calculate the number of hypercubes on each (n-r) D face (r=1,2,...).
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 12 ·
Replies
12
Views
5K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 4 ·
Replies
4
Views
3K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 16 ·
Replies
16
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K