- #1

- 836

- 13

You are using an out of date browser. It may not display this or other websites correctly.

You should upgrade or use an alternative browser.

You should upgrade or use an alternative browser.

- Thread starter qspeechc
- Start date

- #1

- 836

- 13

- #2

- 15,393

- 686

To solve a DE numerically you need not only the differential equations themselves but also information about the state. Initial value techniques are used in the case that the full state is known at some point in the domain. Boundary value techniques (much harder) are used in the case where only parts of the state are known, but at multiple points in the domain.

- #3

- 836

- 13

- #4

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 963

If, for example, you have the second order equation, Y"(x)= f(x, Y, Y'), you could let U(x)= Y' so that your equation becomes U'= f(x, Y, U). Because that equation still involves Y, you need two equations: U'= f(x,Y,U) and Y'= U. Now run two

For example, if you are given Y"= f(x,Y,Y') with initial conditions Y(x

- #5

- 836

- 13

So, iffin I is understannin correkly, first find

U'= f(x,Y,U)

numerically, then from Y'= U find Y?

U'= f(x,Y,U)

numerically, then from Y'= U find Y?

- #6

HallsofIvy

Science Advisor

Homework Helper

- 41,833

- 963

- #7

- 836

- 13

Ah, I think I get it. Probably not. Thank you HallsofIvy

Share:

- Replies
- 1

- Views
- 2K