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dx/dt = c1 / (c2 + c3*x*t)

Does anyone have any input on wether this problem can be approximated?

Thank you.

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- Thread starter CaseyGross
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- #1

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dx/dt = c1 / (c2 + c3*x*t)

Does anyone have any input on wether this problem can be approximated?

Thank you.

- #2

DrClaude

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Do you really mean complex, or simply "complicated?"I've been trying to figure out a way to get an approximation to a complex DiffEQ.

Do you know c1, c2, c3 and x(0)?dx/dt = c1 / (c2 + c3*x*t)

If what you want is a numerical solution, as your title indicates, then it is trivial. What software to you have access to and know how to use (Matlab, Mathematica, C compiler, ...) ?Does anyone have any input on wether this problem can be approximated?

- #3

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The equation again is, dx/dt = c1 / (c2 + c3*x(t)*t) initial value is x(0) = 0.

I have access to Matlab, Mathematica and a C compiler. My preference is Matlab, C, then Mathematica.

Thank you

- #4

DrClaude

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