O"Proving a Trig Identity: Sec^6x-Tan^6x = 1+3Sec^2xTan^2x | Tips & Tricks

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SUMMARY

The discussion focuses on proving the trigonometric identity sec6x - tan6x = 1 + 3sec2x tan2x. Participants explored various methods, including factoring the left-hand side (LHS) as (sec2x - tan2x)(sec4x + sec2x tan2x + tan4x) and applying Pythagorean identities. Ultimately, one participant successfully demonstrated the identity by expanding (tan2x + 1)3 - tan6x, leading to the right-hand side (RHS).

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  • Understanding of basic trigonometric identities
  • Familiarity with factoring polynomials
  • Knowledge of Pythagorean identities
  • Ability to manipulate algebraic expressions
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  • Study advanced trigonometric identities and their proofs
  • Learn techniques for factoring higher-degree polynomials
  • Explore the application of Pythagorean identities in complex proofs
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Students studying trigonometry, mathematics educators, and anyone looking to enhance their skills in proving trigonometric identities.

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Homework Statement



Show that the LHS can be changed into the RHS.
sec^6 x-tan^6x=1+3sec^2x tan^2x


Homework Equations



Trig identities.

The Attempt at a Solution


I tried factoring the LHS:
(sec^2-tan^2)(sec^4+sec^2tan^2+tan^4)
sec^2-tan^2=1 so that leaves me with the other thing in the parentheses. I have tried using the Pythagorean identities on sec^2 and tan^2, I have broken up the sec^4 into sec^2*sec^2...

I just am not getting anywhere.
Pointers would be nice.
CC
 
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i get the RHS le.
try (tan²x+1)³ - tan^6 x
then you expand.
Cheers:smile:

i will be offline , i shall leave the ans in the spoiler (:

next step:
3tan²x+3tan^4 x +1
next:
1+3tan²x(tan²x+1)
Finally:
1+3sec²tan²x
=RHS(shown)
 
Last edited:
I got it easily after the first hint. Thanks! I had been staring at it too long to see another way.
 

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