Object on table pulled by hanging object

  • Thread starter Thread starter pnwguy17
  • Start date Start date
  • Tags Tags
    Table
Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
3 replies · 6K views
pnwguy17
Messages
2
Reaction score
0

Homework Statement


An object of m=0.85kg is on a table. It is attached via pulley to a hanging object of m=0.42kg. The pulley is a hollow cylinder of mass 0.35 kg, with an inner radius of 0.02m and an outer radius of 0.03m, and it turns without friction. The coefficient of friction between the table and first object is 0.25.
The velocity when the object passes a certain reference point is 0.82m/s.

Using energy methods, I am supposed to find the final velocity after the block has moved 0.7m


Homework Equations


Kinetic Energy:
K=1/2(mv^2 )

Rotational kinetic energy:
Kr=1/2(Iω^2)

Potential energy:
U=mgh

Moment of inertia for a hollow cylinder:
I=1/2(M)r1^2+r2^2)

Also, v=r[tex]\omega[/tex]

The Attempt at a Solution


Since energy is conserved through the whole process, the initial kinetic energy of the two blocks plus the initial rotational energy of the pulley plus the potential energy of the hanging block will equal the final kinetic energies of the two blocks plus the final rotational energy of the pulley.

Initial Energy:
(1/2)(0.42)(0.82)^2 + (1/2)(0.85)(0.82)^2 + (1/2)(1/2)(0.35)(0.02^2+0.03^2)*(0.82/00.03)^2 + (0.42)(9.8)(0.7) = (0.141204 + 0.28577 + 0.08498 + 2.8812 = 3.393 joules

Final energy:
(1/2)(0.42)(v^2) + (1/2)(0.85)(v^2) + (1/2)(1/2)(.35)(0.02^2+0.03^2)*(v/00.03)^2 =
0.21v^2 + 0.425v^2 + 0.126v^2 = 0.761v^2

3.393=0.761v^2
v=sqrt(3.393/0.761)= 2.27 m/s

However, my book says that final velocity is 1.59 m/s.

where have i gone wrong? And why isn't the coeffcient of friction used in the equations?
 
Physics news on Phys.org
pnwguy17 said:
1. The coefficient of friction between the table and first object is 0.25.


The Attempt at a Solution


Since energy is conserved through the whole process, ...


Read the problem: there is friction. The mechanical energy is not conserved.

ehild
 
That's true...but since none of the equations call for the friction force, let alone the coefficient of friction, how do I inocrporate it into the problem?
 
Energy conservation is not valid. How much energy is lost because of friction?

ehild