Obtain Normal Vector of Bubble Wall in Spacetime

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John Greger
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TL;DR
Want to compute the normal vector of a bubble wall embedded in a spacetime with metric.
So say I have a bubble embedded in a spacetime with metric:
$$ds^2 = -dt^2 + a(t) ( dr^2 + r^2 d\Omega^2_2) $$

how do I compute the normal vector if I assume the wall of the bubble the metric represents follows a time-like trajectory, for any ##a(t)##?

Since we are interested in dynamical solutions, we let the positions on the brane be ##(t,r, \theta, \phi) \rightarrow (T(\tau), R(\tau), \theta, \phi)##.

Here:
https://arxiv.org/pdf/hep-ph/0003173.pdf
in equation 3,4, they have computed the norm for the brane in a similar fashion but for a different metric. They had ##ds^2 = -u(r) dt^2 + \frac{1}{u(r)}dr^2 + r^2 d\Omega_3^2## and got ##N_a = (-\dot{R}, \dot{T},0,0,0)## so I also expect to have a #\dot{T}# in my normal.
 
on Phys.org
Can you give more information, so that we don't have to read the paper. For instance, this
John Greger said:
Since we are interested in dynamical solutions, we let the positions on the brane be ##(t,r, \theta, \phi) \rightarrow (T(\tau), R(\tau), \theta, \phi)##.
looks like a curve not a surface. Or is this a one parameter family of surfaces, ##\tau## the parameter of the family and ##\theta, \phi## the surface parameters?
 
martinbn said:
Can you give more information, so that we don't have to read the paper. For instance, this

looks like a curve not a surface. Or is this a one parameter family of surfaces, ##\tau## the parameter of the family and ##\theta, \phi## the surface parameters?
Hi!The dot is ##\partial_\tau##. The parameters R and T are coordinates on the bubble wall as functions of proper time. Sorry for not giving more context from the paper, I believe it is not very useful, they more or less just state the norm of a bubble wall in a different spacetime background, but I do not understand how they obtained it either. But I believe it could give a hint on the form of the normal vector I am looking for but I am not sure.
 
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