Optics question - Don't know if anyone can help

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SUMMARY

The discussion centers on solving an optics problem involving Snell's law and the relationships between angles in a cone. The user initially applies Snell's law, stating sin(α) = n sin(β), but struggles to express sin(β) in terms of θ. A key suggestion is to utilize geometry to relate the angles β, γ, and θ, specifically by drawing an auxiliary vertical line at the point where the ray strikes the cone's wall. This geometric approach simplifies the problem and aids in visualizing the relationships between the angles.

PREREQUISITES
  • Understanding of Snell's Law in optics
  • Basic knowledge of geometric relationships in triangles
  • Familiarity with angles and their notations (α, β, γ)
  • Ability to interpret and create geometric diagrams
NEXT STEPS
  • Study the application of Snell's Law in different optical scenarios
  • Learn about geometric optics and the properties of light rays
  • Explore the concept of auxiliary lines in geometry for problem-solving
  • Practice solving optics problems involving multiple angles and refraction
USEFUL FOR

Students preparing for exams in physics, particularly those focusing on optics, as well as educators seeking to enhance their teaching methods in geometric optics.

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I've attached a screenshot of the question, and I have to admit I'm really struggling. I don't know if anyone will be able to help as optics is very diagram-dependent, but perhaps you can give me a hint without needing to draw anything.

I'm stuck on (ii) a)

The first thing I did was use Snell's law to give sin(α)=n sin(β), and that's about as far as I've got in progress. I realize I need to get sin(β) in terms of θ, but nothing I seem to do can get me the answer. Do I need to consider the angle γ as well? I know that n sinγ≈ 1, but I'm just adding another variable to the problem!

(I have an exam soon, hence the sudden influx of questions)
 

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Hello.

See if you can use just geometry to relate the angles β, γ, and θ.

Hint: It might be helpful to draw an auxiliary vertical line through the point where the ray strikes the wall of the cone.
 
Of course! I put the line in every other place but there. Thanks for the help
 

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