What is the optimal number of items to produce for maximum profit in business?

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SUMMARY

The optimal number of items to produce for maximum profit in the given scenario is 5, as determined by the cost function C(n) = n^2 - 6n + 35 and the revenue function R(n) = 50n. The profit function is derived as Profit = 50n - (n^2 - 6n + 35), simplifying to Profit = 56n - n^2 - 35. The critical point for maximum profit occurs at n = 28, but the correct interpretation of the cost function reveals that the manufacturer should produce only 5 items to maximize profit, as confirmed by the textbook.

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Shakattack12
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Homework Statement


A manufacturer makes a batch of n items with the cost (in dollars) of each item being:
n2-6n+35.
The manufacturer sells the items for $50 each. How many items should be produced in each batch to maximise profit.

Homework Equations


Cost = C(n) = n2-6n+35
Revenue = R(n) = 50n

The Attempt at a Solution


Profit = 50n - (n2-6n+35)
= 56n - n2-35
dP/dn = 56 - 2n
let dP/dn = 0
0 = 56 - 2n
n = 28
After testing the nature I found it to be a maximum which is all good but the textbook says the answer is 5. Where did I go wrong?
 
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Shakattack12 said:

Homework Statement


A manufacturer makes a batch of n items with the cost (in dollars) of each item being:
n2-6n+35.
The manufacturer sells the items for $50 each. How many items should be produced in each batch to maximise profit.

Homework Equations


Cost = C(n) = n2-6n+35
Revenue = R(n) = 50n

The Attempt at a Solution


Profit = 50n - (n2-6n+35)
= 56n - n2-35
dP/dn = 56 - 2n
let dP/dn = 0
0 = 56 - 2n
n = 28
After testing the nature I found it to be a maximum which is all good but the textbook says the answer is 5. Where did I go wrong?

Your ##p = n^2 -6n + 35## is the cost per item, so the cost of a batch of ##n## items is ##C(n) = n p##.
 
Thank you so much! Can't believe I missed that.
 

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