Oscillation of a particle inside water caused by a sound wave

[bubble-flow]

Homework Statement

Under water, a flat, sinusoidal sound wave with 1 MHz frequency and 1000 kW/m² intensity hits a round particle with a diameter of 10 microns and a density of 5 kg/m³. It is stimulated to oscillate in the longitudinal direction. How big is the amplitude of this movement?

Relevant Equations

No equations given

I don't really know where to start as this is not exactly my homework and I finished school some 15 years ago. I looked into my old high school notes, the last time I ever had anything about mechanical waves and sound. Unfortunately, we never learned anything about sound waves causing oscillation in a 2-phase flow, so I don't even know what to google for an explanation or appropriate equations.
So far this is what I have:

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[mitochan]

Hi.

I just estimate order of the amplitude.
Mass of the particle is
$$\frac{3}{4}\pi (10\times10^{-6})^3\ m^3 \times 5\ kg/m^3\ \equiv M$$
The area that particle receives energy is
$$\pi(10/2\times 10^{-5})^2\ m^2$$
So energy the particle get is
$$\pi(10/2\times 10^{-5})^2\ \times 10^6\ W$$
During a pair of push pull time of $10^{-6}$ seconds input energy is
$$\pi(10/2\times 10^{-5})^2\ \times 10^6\times 10^{-6} \ Joule\ \equiv E$$

In stationary case where input energy dissipates, we may estimate the above energy is average Kinetic Energy whose formula is
$$E=\frac{1}{2}Mv^2$$
average absolute value of velocity is
$$|v|=\sqrt{2E/M}$$
We get order of displacement amplitude as
$$|v|\times 10^{-6} \ m$$
it is calculated order of $m\ m$.