Oscillation of nonrelativistic Strings

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SUMMARY

The discussion focuses on calculating the horizontal force (dFhorizontal) of a string and demonstrating that for small oscillations, this force is significantly smaller than the vertical force (dFvertical) responsible for transverse oscillations. The equations used include T0(d^2 y/d^2 x)dx=(μ0dx)d^2 y/dt^2 and dFhorizontal=T0(dx/dy)*(-T0(dx/dy)*1). The conclusion emphasizes expressing both forces in terms of y(x) and its derivatives to facilitate comparison, particularly under the assumption that dy/dx is much less than 1.

PREREQUISITES
  • Understanding of nonrelativistic string dynamics
  • Familiarity with differential equations
  • Knowledge of tension in strings (T0) and mass per unit length (μ0)
  • Basic principles of oscillatory motion
NEXT STEPS
  • Study the derivation of wave equations for strings under tension
  • Learn about small angle approximations in oscillatory systems
  • Explore the relationship between tension and oscillation frequency in strings
  • Investigate the effects of boundary conditions on string oscillations
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This discussion is beneficial for physics students, particularly those studying classical mechanics and wave dynamics, as well as educators seeking to clarify concepts related to string oscillations and forces involved.

moriheru
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Homework Statement


Calculate the horizontal force dFhorizontal of a string .Show that for small oscillations this force is much smaller than the vertical force dFvertical responsible for the transverse oscillations.
[I apolagize for the way the equations are written]

Homework Equations



dFvertical=T0dy/dx*-T0dy/dx*1
*for x+dx *1 for x

T0(d^2 y/d^2 x)dx=(μ0dx)d^2 y/dt^2

3. The Attempt at a Solution

1.substituting y+dy and y for x+dx and x; substituting dx/dy for dy/dx for horizontal oscillation.
dFhorizontal=T0dx/dy*-T0dx/dy*1
*for y+dy *1 for y
2.exchanging d^2 y/ dx^2 with d^2 x/dy^2 and dx with dy...

T0 (d^2 x/dy^2) dy= (μ0dx)(d^2 x/dt^2)

This is as far as I get. I don't know how to show that the horizontal force is smaller than the vertical force for small oscillations.

Thanks for any clarifications and corrections.
 
Last edited:
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I would instead express the forces (both horizontal and verical) in terms of y(x) and its derivatives wrt x. You can then compare the two with the assumption of small oscillations giving you dy/dx << 1.
 

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