Pair Annihilation and Conservation of Momentum and Energy Explained

Click For Summary
SUMMARY

The discussion centers on the annihilation of an electron and positron, resulting in two photons that conserve momentum and energy. The key equations involve conservation of momentum (p1 - p2) and conservation of energy (p1c + p2c). The confusion arises in the subsequent step where both results are added to solve for p1 and p2. The solution is clarified through algebraic manipulation, demonstrating that adding the equations simplifies the process of isolating the variables.

PREREQUISITES
  • Understanding of conservation laws in physics, specifically momentum and energy.
  • Familiarity with photon momentum and its relation to energy (E=pc).
  • Basic algebra skills for solving simultaneous equations.
  • Knowledge of particle physics concepts, particularly electron-positron interactions.
NEXT STEPS
  • Study the principles of conservation of momentum and energy in particle physics.
  • Learn about photon properties and their role in particle interactions.
  • Practice solving simultaneous equations in physics contexts.
  • Explore advanced topics in quantum mechanics related to particle annihilation.
USEFUL FOR

Students of physics, particularly those focusing on particle physics, educators teaching conservation laws, and anyone interested in the mathematical aspects of energy and momentum in particle interactions.

jk4
I'm a little unsure about a certain part of this shown in a book.
There is an electron and a positron moving in the +x direction. They annihilate each other and release 2 photons. to conserve momentum 1 moves in the -x and one in the +x direction.
So then the first step is to do conservation of momentum: p_{1} - p_{2} (photon momentum 1 - photon momentum 2). It's a (-) because the second photon moves in the -x direction.

Then we find conservation of energy: p_{1}c + p_{2}c
(obviously we set these equations equal to the electron values, but I'm leaving that out.)

Ok, so, they find values for both of those equations. But, what I'm not sure of is the next step. It says
"Now we add the two results and solve for p_{1} and p_{2}
so it looks like:
(p_{1} - p_{2}) + (p_{1} + p_{2})

Then I understand the rest, I just don't know why they add the 2 values. Total Energy and net Momentum.
 
Physics news on Phys.org
jk4 said:
… conservation of momentum: p_{1} - p_{2} (photon momentum 1 - photon momentum 2). It's a (-) because the second photon moves in the -x direction.

Then we find conservation of energy: p_{1}c + p_{2}c

Ok, so, they find values for both of those equations. But, what I'm not sure of is the next step. It says
"Now we add the two results and solve for p_{1} and p_{2}
so it looks like:
(p_{1} - p_{2}) + (p_{1} + p_{2})

Then I understand the rest, I just don't know why they add the 2 values. Total Energy and net Momentum.

Hi jk4! :smile:

You have p1 + p2 = A, p1 - p2 = B.

If you add: 2p1 = A + B, and 2p2 = A - B.

So that gives you p1 and p2. :smile:

What worries you about that? :confused:

(How else would you solve it?)
 
(How else would you solve it?)
That's why I asked. I like to learn things in a way that I don't have to do much memorizing, but so that it will be obvious to me if I ever come across it.
So I'm just not sure this will be that obvious to me.. Might have to actually consult my notes :(

Sorry, It just threw me because I'm not sure what is the significance of momentum+totalEnergy
 
jk4 said:
That's why I asked. I like to learn things in a way that I don't have to do much memorizing, but so that it will be obvious to me if I ever come across it.
So I'm just not sure this will be that obvious to me.. Might have to actually consult my notes :(

Sorry, It just threw me because I'm not sure what is the significance of momentum+totalEnergy

Your initial question is confusing because you don't say what information was provided to you. I am assuming that they gave you the total momentum and energy of the e-e+ pair, right?


Forget about particle physics for a second. It's just algebra. Let's say you have to solve

x+y = 10

x-y = 6

How would you solve that? There is not a single way. You could isolate x from the first equation and plug in the second and then solve for y. But the quick way is of course to add them up to get rid of y.

well, this is basically exactly the same type of algebra problem you are dealing with here except that your unknowns are p1 and p2. That's all there is to it.
 

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 16 ·
Replies
16
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 23 ·
Replies
23
Views
4K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 10 ·
Replies
10
Views
1K