Parameterizing conditional expectations (Gaussian case)

Join the discussion
Registration is free. Ask a follow-up in this thread, or start your own.
2 replies · 2K views
estebanox
Messages
26
Reaction score
0
Consider three jointly normally distributed random variables X,Y and Z.

I know that in the Gaussian case E[Z | X,=x Y=y]=xßZX;Y +yßZY;X
where ßZX;Y notes the regression coefficient of Z on X conditional on Y (and ßZY;Xis analogously defined).

Is the following derivation correct?

E[Z| X>x, Y<y] = E [ E[Z | X,Y] | X>x, Y<y]
ZX;Y E[X | X>x, Y<y]+ßZY;X E[Y |X>x, Y<y]
 
Physics news on Phys.org
Yes it is correct.
The first equality is an application of the Tower Law.
The second equality actually comprises two steps:
1. substitute your formula for E[Z | X,Y] from above for the inner expectation
2. Use the linearity of the expectation operator and the fact that the betas are constants to get the result.
 
  • Like
Likes   Reactions: mfb
andrewkirk said:
Yes it is correct.
The first equality is an application of the Tower Law.
The second equality actually comprises two steps:
1. substitute your formula for E[Z | X,Y] from above for the inner expectation
2. Use the linearity of the expectation operator and the fact that the betas are constants to get the result.
Great! Thanks a lot for spelling it out