Parametric equations to find surface area

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SUMMARY

The discussion focuses on calculating the surface area of a solid obtained by rotating the parametric curve defined by x=t-t² and y=(4/3)t^(3/2) for the interval 1 PREREQUISITES

  • Understanding of parametric equations
  • Knowledge of calculus, specifically integration techniques
  • Familiarity with derivatives and their applications
  • Experience with surface area calculations in 3D geometry
NEXT STEPS
  • Study the derivation of surface area formulas for parametric curves
  • Learn about the application of the integral A = integral (2πy * sqrt(1 + (dy/dx)²))dx
  • Explore the concept of rotation of curves around axes in calculus
  • Practice solving similar problems involving parametric equations and surface area
USEFUL FOR

Students studying calculus, particularly those focusing on parametric equations and surface area calculations, as well as educators seeking to enhance their teaching methods in these topics.

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Homework Statement


Which of the following integrals represents the area of the surface obtained by rotating the parametric curve
x=t-t^2
y=(4/3)t^(3/2)
1<t<2

Homework Equations


A = integral ( 2pi(y) * sqrt( 1+ (dy/dx)^2))dx


The Attempt at a Solution


I solved for dy/dx and got
12(t^1/2) / (9-18t)
and then plug (1-2t)dt in for dx
and (4/3)t^3/2 for y

If i plug these all in and algebra correctly will i get the correct answer?
How do i include the information that it's being rotated around the x-axis into my equation?
 
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If i plug these all in and algebra correctly will i get the correct answer?
That should give the right answer. You can simplify your dy/dx, by the way.

How do i include the information that it's being rotated around the x-axis into my equation?
Your equation at (2.) takes care about that.
 

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