Parsing the Fibers of Critical Values

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SUMMARY

The discussion focuses on the mathematical analysis of fibers at critical values of the map f(z1,z2): ℂ2→ℂ, defined by f(Z1, Z2) = Z12 + Z22 = 0. The transformation to ℝ4→ℝ2 reveals that the Jacobian matrix is [2x1, 2y1, 2x2, 2y2; 2y1, 2x1, 2y2, 2x2]. The only critical value identified is (0,0), leading to the conclusion that the fibers of non-zero values are submanifolds of ℂ2. The general fiber, when restricted to (x1,x2, 0, 0), forms a circle, while the collection of all fibers forms a cone.

PREREQUISITES
  • Understanding of complex functions and mappings, specifically ℂ2 to ℂ transformations.
  • Familiarity with Jacobian matrices and their significance in multivariable calculus.
  • Knowledge of the inverse function theorem and implicit function theorem.
  • Basic concepts of submanifolds in differential geometry.
NEXT STEPS
  • Explore the implications of the inverse function theorem in higher dimensions.
  • Study the properties of Jacobian matrices in relation to critical points.
  • Investigate the geometric interpretation of fibers and submanifolds in complex analysis.
  • Research the classification of fibers in terms of isomorphism and their topological properties.
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Mathematicians, particularly those specializing in complex analysis, differential geometry, and multivariable calculus, will benefit from this discussion.

WWGD
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Hi, All:

I am trying to better understand what happens at fibers of critical values:

Specifically, I had the fibers of the map:

f(z1,z2): ℂ2→ℂ , given by:

f(Z1, Z2)= Z12+z22 =0

I rewrote it as a map from ℝ4→ℝ2=

f(x1,y1,x2,x2)=

(x12-y12+x22-

y22 , x1y1+2x2y2)Which has the Jacobian:
(Sorry, I don't know how to Tex a matrix ):

[ 2x1, 2y1, 2x2, 2y2 ]

[ 2y1, 2x1, 2y2, 2x2


Now, by one of the family of theorems in { inverse function, implicit function, regular rank theorem} , the fibers of the non-zero values are submanifolds of ℂ2.

After row-reducing, we get that the only critical value is (0,0) .

Now, some work on f{-1}(0,0):

i)Not very helpful: Z12+Z22=0

implies Z1=iZ2.

ii) A little better:

Restricting to (x1,x2, 0, 0):

Then the general fiber is a circle, and the collection of all fibers is a cone .

Is there anything else we can do to get a better understanding of what the general

fibers are like ? I think all the regular fibers are isomorphic to each other--tho I cannot

find a good proof -- and then we have the critical fiber.

Any ideas?

Thanks.
 
Last edited:

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