Partial Differntial problem Cauchy

  • Context: MHB 
  • Thread starter Thread starter arrow27
  • Start date Start date
  • Tags Tags
    Cauchy Partial
Click For Summary
SUMMARY

The discussion focuses on solving a Cauchy problem involving a partial differential equation defined by the equation ${a^2} \cdot {x_2} \cdot u \cdot {u_{{x_1}}} + {b^2} \cdot {x_1} \cdot u \cdot {u_{{x_2}}} = 2{c^2}{x_1}{x_2}$. The equation is constrained by the boundary condition represented by the ellipse ${\rm{ C: = \{ }}\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1,{x_3} = u({x_1},{x_2}) = 0\}$. Participants suggest maintaining consistent notation and consider transforming to new coordinates using $x = a r \cos \theta$ and $y = b r \sin \theta$ to simplify the problem.

PREREQUISITES
  • Understanding of partial differential equations (PDEs)
  • Familiarity with boundary value problems
  • Knowledge of coordinate transformations in multivariable calculus
  • Experience with the Cauchy problem in mathematical analysis
NEXT STEPS
  • Research methods for solving Cauchy problems in PDEs
  • Learn about coordinate transformations and their applications in solving PDEs
  • Study the properties of ellipses and their implications in boundary conditions
  • Explore numerical methods for approximating solutions to PDEs
USEFUL FOR

Mathematicians, physicists, and engineers dealing with partial differential equations, particularly those focused on boundary value problems and coordinate transformations.

arrow27
Messages
7
Reaction score
0
Find surface of

$\begin{array}{l}
\text{Problem Cauchy} \\
{a^2} \cdot {x_2} \cdot u \cdot {u_{{x_1}}} + {b^2} \cdot {x_1} \cdot u \cdot {u_{{x_2}}} = 2{c^2}{x_1}{x_2}{\rm{ }} \\
\end{array}$
The partial differential equation passes through

${\rm{ C: = \{ }}\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1,{x_3} = u({x_1},{x_2}) = 0\} \\
\\ $$a,b,c$ nonzero constants
 
Last edited:
Physics news on Phys.org
First. I think you should be consistent with your notation. Either use $$x$$ and $$y$$ or $$x_1$$ and $$x_2$$ but not both. It's confusing.

Second, as you have the boundary of an ellipse, have you thought of introducing new coordinates

$$x = a r \cos \theta, y = b r \sin \theta?$$
 
Last edited:
Ιn C are x1,y1.
 
Last edited:

Similar threads

  • · Replies 9 ·
Replies
9
Views
3K
  • · Replies 7 ·
Replies
7
Views
3K
  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 17 ·
Replies
17
Views
3K
  • · Replies 1 ·
Replies
1
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
8
Views
4K
Replies
0
Views
2K