Partial Pressure of O2: 99.3 KPa at 25°C & Water

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SUMMARY

The partial pressure of oxygen gas (O2) collected over water at 25°C with an atmospheric pressure of 99.3 KPa can be calculated using the formula P total = P O2 + P H2O. At 25°C, the vapor pressure of water (P H2O) is approximately 3.17 KPa. Therefore, the partial pressure of oxygen (P O2) is determined by subtracting the vapor pressure of water from the total atmospheric pressure, resulting in P O2 = 99.3 KPa - 3.17 KPa = 96.13 KPa. This value can be converted to mmHg by using the conversion factor of 1 KPa = 7.50062 mmHg, yielding a final result of approximately 721.5 mmHg.

PREREQUISITES
  • Understanding of gas laws, specifically Dalton's Law of Partial Pressures
  • Knowledge of vapor pressure and its dependence on temperature
  • Ability to perform unit conversions between KPa and mmHg
  • Familiarity with basic chemistry concepts related to gases
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Chemistry students, educators, and anyone preparing for exams related to gas laws and thermodynamics will benefit from this discussion.

fatima_a
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what is the partial pressure of oxygen gas. if it is collected over water at 25 degrees celsius and an atmospheric pressure of 99.3 KPa. answer in mmHg

okay i know the formula for partial pressures is

P total = P O2 + P H2O

but there is no other info given like the volume or anything so i am lost. please answer by tomorrow. and show all the steps. i have a quiz the day after
 
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There should be a discussion of how H20 pressure varies with temperature, either in your textbook or class lecture notes. You might try looking up "vapor pressure" or "pressure, vapor" in the index of your textbook.
 

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