Particle Uniform circular motion problem

[J-dizzal]

Homework Statement

A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 3.30 s, it is at point (5.10 m, 6.80 m) with velocity (3.90 m/s) $\hat j$and acceleration in the positive x direction. At time t2 = 9.90 s, it has velocity (–3.90 m/s) $\hat i$and acceleration in the positive y direction. What are the (a) x and (b) y coordinates of the center of the circular path? Assume at both times that the particle is on the same orbit.

Homework Equations

a=v²/r

The Attempt at a Solution

im having trouble getting started on this one. if only drawn a diagram with the particles plotted along the orbit and their tangential velocity vectors
the point at t=3.30s is on the very left of the orbit and the point at t=9.90s is on the very bottom of the orbit.
the center point of the circle is in quadrant 1

https://www.dropbox.com/s/x36hlpj0btsrl9u/20150622_205717.jpg?dl=0

 

[phinds]

And you don't care to share your drawing here because ... ?

 

[J-dizzal]

And you don't care to share your drawing here because ... ?

added a link to my sketch, not sure how to insert that as an image on here.

 

[J-dizzal]

anyone have any ideas how to get this problem going? I am trying to find t first but no luck

 

[SammyS]

https://photos-1.dropbox.com/t/2/AACGiRWI3VnMU6pGc_dHKBaqChMthL4b3OjGjbIWmGkYHA/12/424149441/jpeg/32x32/1/1435046400/0/2/20150622_205717.jpg/CMGDoMoBIAEgAiADIAQgBSAGIAcoAg/9Z_NSs16LlnutIe8w5k1a-Inu6pHLS32aoGOxFwQbXg?size_mode=5

View the image. Then copy that image you're viewing. Then paste it here.

It is quite difficult to read.