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Particle Uniform circular motion problem

  1. Jun 22, 2015 #1
    1. The problem statement, all variables and given/known data
    A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 3.30 s, it is at point (5.10 m, 6.80 m) with velocity (3.90 m/s) ## \hat j ##and acceleration in the positive x direction. At time t2 = 9.90 s, it has velocity (–3.90 m/s) ## \hat i ##and acceleration in the positive y direction. What are the (a) x and (b) y coordinates of the center of the circular path? Assume at both times that the particle is on the same orbit.

    2. Relevant equations
    a=v2/r

    3. The attempt at a solution
    im having trouble getting started on this one. if only drawn a diagram with the particles plotted along the orbit and their tangential velocity vectors
    the point at t=3.30s is on the very left of the orbit and the point at t=9.90s is on the very bottom of the orbit.
    the center point of the circle is in quadrant 1

    https://www.dropbox.com/s/x36hlpj0btsrl9u/20150622_205717.jpg?dl=0
     
    Last edited: Jun 22, 2015
  2. jcsd
  3. Jun 22, 2015 #2

    phinds

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    And you don't care to share your drawing here because ... ?
     
  4. Jun 22, 2015 #3
    added a link to my sketch, not sure how to insert that as an image on here.
     
  5. Jun 22, 2015 #4
    anyone have any ideas how to get this problem going? im trying to find t first but no luck
     
  6. Jun 23, 2015 #5

    SammyS

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    https://photos-1.dropbox.com/t/2/AACGiRWI3VnMU6pGc_dHKBaqChMthL4b3OjGjbIWmGkYHA/12/424149441/jpeg/32x32/1/1435046400/0/2/20150622_205717.jpg/CMGDoMoBIAEgAiADIAQgBSAGIAcoAg/9Z_NSs16LlnutIe8w5k1a-Inu6pHLS32aoGOxFwQbXg?size_mode=5 [Broken]

    View the image. Then copy that image you're viewing. Then paste it here.

    It is quite difficult to read.
     
    Last edited by a moderator: May 7, 2017
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