# Particle Uniform circular motion problem

1. Jun 22, 2015

### J-dizzal

1. The problem statement, all variables and given/known data
A particle moves along a circular path over a horizontal xy coordinate system, at constant speed. At time t1 = 3.30 s, it is at point (5.10 m, 6.80 m) with velocity (3.90 m/s) $\hat j$and acceleration in the positive x direction. At time t2 = 9.90 s, it has velocity (–3.90 m/s) $\hat i$and acceleration in the positive y direction. What are the (a) x and (b) y coordinates of the center of the circular path? Assume at both times that the particle is on the same orbit.

2. Relevant equations
a=v2/r

3. The attempt at a solution
im having trouble getting started on this one. if only drawn a diagram with the particles plotted along the orbit and their tangential velocity vectors
the point at t=3.30s is on the very left of the orbit and the point at t=9.90s is on the very bottom of the orbit.
the center point of the circle is in quadrant 1

https://www.dropbox.com/s/x36hlpj0btsrl9u/20150622_205717.jpg?dl=0

Last edited: Jun 22, 2015
2. Jun 22, 2015

### phinds

And you don't care to share your drawing here because ... ?

3. Jun 22, 2015

### J-dizzal

added a link to my sketch, not sure how to insert that as an image on here.

4. Jun 22, 2015

### J-dizzal

anyone have any ideas how to get this problem going? im trying to find t first but no luck

5. Jun 23, 2015

### SammyS

Staff Emeritus