MHB Particle Velocity at Instaneous Rest: 3${t}^{2}-{t}^{2}+C$

[karush]

View attachment 5147
$\int v(t) dt = 3{t}^{2}-{t}^{2}+C$
What does is next at instaneous rest mean?
Wouldn't that be zero?

 

[Prove It]

What have you tried so far?

 

[karush]

See OP
I have to use a cell phone to upload an image. The upload button does not appear on a Samsung tablet. Not to mention all page clipping on the image manager.

The answers were
(a) $-6 \ m \ {s}^{-2}$
(b) 4 m

 

[Prove It]

Instantaneous rest means that there is a point in time where the particle is not moving - so has a zero velocity.

 

[karush]

$v\left(t\right)=0$ at t=0 and t=2
$a\left(2\right)=4$
It should be -6?

 

[Prove It]

Acceleration is the derivative of velocity, not the antiderivative.

 

[karush]

Got it, yeah that worked