Particle Velocity at Instaneous Rest: 3${t}^{2}-{t}^{2}+C$

  • Context: MHB 
  • Thread starter Thread starter karush
  • Start date Start date
  • Tags Tags
    Particle Velocity
Click For Summary

Discussion Overview

The discussion revolves around the concept of instantaneous rest in the context of particle motion, specifically examining the relationship between velocity and acceleration as expressed in the equation $\int v(t) dt = 3{t}^{2}-{t}^{2}+C$. Participants explore the implications of a particle being at rest and the calculations related to velocity and acceleration.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested, Mathematical reasoning

Main Points Raised

  • One participant questions the meaning of "instantaneous rest," suggesting it implies zero velocity.
  • Another participant clarifies that instantaneous rest refers to a specific moment when the particle is not moving, thus having zero velocity.
  • A participant notes that the velocity is zero at t=0 and t=2, while also mentioning an acceleration value of 4 m/s² at t=2, questioning if it should be -6 m/s² instead.
  • There is a correction regarding the relationship between acceleration and velocity, stating that acceleration is the derivative of velocity, not the antiderivative.
  • One participant acknowledges a previous misunderstanding and confirms that their revised approach worked.

Areas of Agreement / Disagreement

The discussion contains multiple competing views regarding the calculations of velocity and acceleration, and it remains unresolved whether the acceleration should be -6 m/s² or 4 m/s².

Contextual Notes

Participants express uncertainty about the implications of their calculations and the definitions involved, particularly regarding the relationship between velocity and acceleration.

karush
Gold Member
MHB
Messages
3,240
Reaction score
5
View attachment 5147
$\int v(t) dt = 3{t}^{2}-{t}^{2}+C$
What does is next at instaneous rest mean?
Wouldn't that be zero?
 
Last edited:
Physics news on Phys.org
What have you tried so far?
 
See OP
I have to use a cell phone to upload an image. The upload button does not appear on a Samsung tablet. Not to mention all page clipping on the image manager. 😥

The answers were
(a) $-6 \ m \ {s}^{-2}$
(b) 4 m
 
Last edited:
Instantaneous rest means that there is a point in time where the particle is not moving - so has a zero velocity.
 
$v\left(t\right)=0$ at t=0 and t=2
$a\left(2\right)=4$
It should be -6?
 
Acceleration is the derivative of velocity, not the antiderivative.
 
Got it, yeah that worked
 

Similar threads

Replies
4
Views
2K
  • · Replies 7 ·
Replies
7
Views
563
  • · Replies 2 ·
Replies
2
Views
1K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 10 ·
Replies
10
Views
2K
  • · Replies 2 ·
Replies
2
Views
1K