Path dependence (Complex Analysis)

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The integrals of the function f(z) = (1/(z-2) + (1/(z+1) + e^(1/z) are not path independent in the domain {Rez>0}∖{2}. This is determined by evaluating closed contours in the domain, specifically those that encircle the singularity at z=2. Since the integral around any closed path that winds around z=2 yields a non-zero value, specifically an integer multiple of 2πi, path independence is violated. The easiest method to demonstrate this is through the second equivalent form of path independence, which states that the integral over a closed contour must equal zero. Thus, the presence of the singularity confirms that the integrals are path dependent.
Matt100
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Are the integrals of the function f(z) = (1/(z-2) + (1/(z+1) + e^(1/z)

path independent in the following domain: {Rez>0}∖{2}

The domain is not simply connected

I know that path independence has 3 equivalent forms
that are

1) Integrals are independent if for every 2 points and 2 contours lying completely in the domain the integral along the first contour = the integral along the second contour

2) For every closed contour lying in the domain, the integral over that contour is 0 the integral over that contour is = 0

3) There exists a F(z) in the domain such that F'(z) = f(z) over the entire domain.

Which one of these can be used to show whether the integrals of f(z) = (1/(z-2) + (1/(z+1) + e^(1/z) are path dependent or not in the domain {Rez>0}∖{2}.

It seems like number 2 is the easiest to use but not sure how?
 
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Matt100 said:
Are the integrals of the function f(z) = (1/(z-2) + (1/(z+1) + e^(1/z) path independent in the following domain: {Rez>0}∖{2}
No. If the integrals are path independent, the integral across the closed loop consisting of path1 up and path2 down must be 0. But the integral across any closed path that winds 1 or more times around z=2 is an integer multiple of 2πi.
 

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