Percent efficiency of three power generators

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SUMMARY

The discussion focuses on calculating the efficiency of three coal power generators used to supply energy to a small city. Each generator consumes 1.22 X 10^8 J of chemical energy per hour, leading to a total annual consumption of 3.14 X 10^12 J. The city's annual energy consumption is 1.61 X 10^12 J. Given the lack of information regarding energy loss or conversion, the efficiency cannot be definitively calculated, as the output energy is assumed to equal the input energy without any losses.

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A coal power plant with three power generators is used to power a small city. If each generator uses 1.22 X 10^8 J of chemical energy in the coal every hour, and the average annual energy consumption of the city is 1.61 X 10^12 J. What is the efficiency of the generators?
(Assume the generators run 24 hours a day 365 days a year)

SO here's what I've got so far:

(1.22 X 10^8 J)(3 generators)= 3.6 X 10^8 J used per hour for 3 generators.
(3.6 X 10^8 J)(24H)= 8.6 X 10^9 J consumed in 24 Hours or 1 Day.
(8.6 X 10^9 J)(365 Days)= 3.14 X 10^12 J consumed per year.

So I know how much energy the generators consume but how do I figure out the annual energy output of the generators, and what kind of energy would it be?

1.61 X 10^12 J= Cities annual energy consumption
 
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The question gives no information about loss or conversion going from the generators' output to consumption in the city so you have to assume there is none; they are the same in both size and "kind of energy"; what comes out of the generators is consumed in the city.
 
so there is really no answer for this question then because there is not enough information?
 

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