Photon Polarization: What are indices i and j?

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    Photon Polarization
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Discussion Overview

The discussion revolves around the completeness relation for photon polarization, specifically addressing the indices i and j in the equation ## \sum_{s=1,2}\epsilon_i^s\epsilon_j^{s*}=\delta_{ij}-p_ip_j##. Participants are exploring the implications of these indices and their relationship to the right-hand side of the equation.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • One participant expresses confusion about the indices i and j, suggesting they represent vector components and questioning why the right-hand side would not be zero.
  • Another participant questions the reasoning behind the assumption that the right-hand side would be zero.
  • A third participant attempts to clarify the situation by stating that if i equals j, then ##\delta_{ij}## would equal 1, but also notes that ##p_ip_j## would equal 0 under certain conditions, leading to a misunderstanding of the equation.
  • A later reply corrects the previous claim by emphasizing that ##p## is a fixed vector and that ##p_i## refers to its ith component, suggesting a misunderstanding of the notation.

Areas of Agreement / Disagreement

Participants do not appear to reach a consensus on the interpretation of the indices i and j, with multiple competing views and misunderstandings present in the discussion.

Contextual Notes

There are limitations in the understanding of the notation and the implications of the completeness relation, particularly regarding the definitions of the indices and the components of the vector involved.

Silviu
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Hello! I am a bit confused about the completeness relation for photon polarization. So it says ## \sum_{s=1,2}\epsilon_i^s\epsilon_j^{s*}=\delta_{ij}-p_ip_j##, with ##p_i, p_j## - unit vectors. So I am not sure what are the indices i and j. I though that they represent the component of the vector, but in that case the RHS would be always 0. So what are i and j? Thank you!
 
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Why do you think the RHS would be zero?
 
Orodruin said:
Why do you think the RHS would be zero?
if i=j, ##\delta_{ij}=0## and ##p_ip_j=0## as ##p_i=(1,0,0)## and ##p_j=(0,1,0)##, for example. If i=j, ##\delta_{ii}=1## and ##p_ip_i=1## so in both cases the difference is 0, right?
 
Not right. ##p## is a fixed vector, ##p_i## is its ith component.
 

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