Photons violate Uncertainty Principle?

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SUMMARY

The discussion centers on the relationship between photons and the Heisenberg Uncertainty Principle (HUP). It establishes that while the speed of a photon is known (the speed of light), this does not violate the HUP because a well-defined position operator does not exist for photons. Instead, the uncertainty in a photon's momentum, which can be described by its wavelength or frequency, compensates for the knowledge of its speed. The Heisenberg-Robertson uncertainty relation applies to massive particles, indicating that both position and momentum cannot be precisely determined simultaneously.

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sarvesh0303
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A photon is considered as a quantum particle, right?
However since we know the speed of a photon(speed of light) and hence can predict its position, isn't it violating the Heisenberg Uncertainty Principle?
Where am I going wrong? Is it false to believe that a photon is a quantum particle?
 
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isnt it momentum vs position? so even though we know its speed we might be limited in knowing its momentum (ie wavelength or its frequency) .
 
It's a bit difficult to talk about a photon's position since there doesn't exist a well-defined position operator for a photon.

For massive particles, there is a position operator, fulfilling the Heisenberg algebra
[\hat{x}_i,\hat{p}_j]=\mathrm{i} \hbar \delta_{ij}.
Then for any pure or mixed state the Heisenberg-Robertson uncertainty relation,
\Delta x_i \Delta x_j \geq \frac{\hbar}{2} \delta_{ij}
holds. I tells you that the position and momentum of the particle both are not fully determined but distributed with a finite standard deviation, and the product of these standard deviations cannot be smaller than \hbar/2 if you consider position and momentum components in the same direction.
 

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