Physical Interpretation of a Vector Quantity

In summary, the conversation discusses the physical significance of the vector quantity [\mathbf{a} \cdot (\mathbf{v} \times \mathbf{r})] and its relationship to the acceleration vector \mathbf{a}, velocity vector \mathbf{v}, and position vector \mathbf{r}. It is shown that this vector quantity is a measure of the parallelism between the acceleration vector and the normal vector of the plane created by \mathbf{v} and \mathbf{r}. If the dot product is zero, the acceleration vector is orthogonal to the plane and if it is non-zero, the acceleration vector has a component parallel to the plane's normal, causing the particle to spiral away from the
  • #1
Bashyboy
1,421
5

Homework Statement


If [itex]\mathbf{r}, \mathbf{v},\mathbf{a}[/itex] denote the position, velocity, and acceleration of a particle, prove that

[itex]\frac{d}{dt} [\mathbf{a} \cdot (\mathbf{v} \times \mathbf{r})] = \dot{ \mathbf{a}} \cdot (\mathbf{v} \times \mathbf{r})[/itex]

Homework Equations


The Attempt at a Solution



I have already proven the result, but am now wondering the what the physical significance of this vector quantity is. I believe I have some idea:

The vectors [itex]\mathbf{v}[/itex] and [itex]\mathbf{r}[/itex] create their own two dimensional subspace (a plane) in [itex]\mathbb{R}^3[/itex], with [itex]\mathbf{v} \times \mathbf{r}[/itex] being normal to this plane. The dot product of this with the acceleration vector [itex]\mathbf{a}[/itex] gives the projection of the acceleration vector onto the normal vector, it is a measure of how parallel they are. If the dot product is zero, then this implies [itex]\mathbf{a}[/itex] is orthogonal to the vector [itex]\mathbf{v} \times \mathbf{r}[/itex], and that it lies in the plane [itex]\mathbf{v}[/itex] and [itex]\mathbf{r}[/itex] create. If it is not zero, then the this implies that the acceleration vector has a component lying in the plane, and a component parallel to the normal of the plane. This causes the particle to spiral away from the plane.

Does this seem correct?
 
Last edited:
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  • #2
Can you define your notation better?

The question says ##\mathbf{a}## denotes the position. In your solution you say it is the acceleration vector.

What do ##\mathbf{b}## and ##\mathbf{c}## have to do with the question?

And what are ##\mathbf{v}## and ##\mathbf{r}##?

:confused::confused::confused:
 
  • #3
Whoops, I am terribly sorry. I just edited my original post.
 
  • #5


Yes, your interpretation is correct. The quantity \mathbf{a} \cdot (\mathbf{v} \times \mathbf{r}) is known as the "angular velocity" of the particle, and it represents the rate at which the particle is changing direction in its motion. This can be visualized as the particle rotating around the axis defined by \mathbf{v} \times \mathbf{r}. The dot product with \mathbf{a} then represents the component of the acceleration that is tangential to this rotation, while the cross product \mathbf{v} \times \mathbf{r} represents the normal component. This is a useful concept in understanding the motion of objects in three-dimensional space, and can be applied to a variety of physical systems, such as rotating objects or particles in circular motion.
 

1. What is a vector quantity?

A vector quantity is a mathematical quantity that has both magnitude and direction. Examples of vector quantities include velocity, force, and displacement.

2. How is a vector represented?

A vector is represented by an arrow, with the length of the arrow indicating the magnitude of the vector and the direction of the arrow indicating the direction of the vector.

3. What is the difference between a vector and a scalar?

A scalar is a mathematical quantity that only has magnitude, while a vector has both magnitude and direction. Examples of scalars include temperature and mass.

4. What is the physical interpretation of a vector quantity?

The physical interpretation of a vector quantity describes the real-world meaning or significance of the vector. For example, the velocity vector of an object can represent the object's speed and direction of motion.

5. How is the physical interpretation of a vector quantity determined?

The physical interpretation of a vector quantity is determined by its mathematical properties and the context in which it is used. It is important to consider the units, direction, and magnitude of the vector in order to understand its physical interpretation.

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