Physics 11 Final exams Practice

Click For Summary
SUMMARY

The discussion focuses on solving physics problems related to gravitational force and lens optics, specifically for a shuttle orbiting Earth and image formation through lenses. Key calculations involve determining the Earth's gravitational field strength at a height of 2.45 x 107 m, with options including 0.39 m/s2 and 1.29 m/s2. Additionally, participants discuss the use of the lens equation and magnification to find image height and position, with a convex lens focal length of 20 cm and a convex mirror focal length of 8 cm. The forum encourages sharing problem-solving methods and understanding relevant equations.

PREREQUISITES
  • Understanding of gravitational force calculations using Newton's law of gravitation.
  • Familiarity with the lens equation and magnification concepts in optics.
  • Knowledge of basic physics principles related to forces and motion.
  • Ability to manipulate and interpret scientific equations and units.
NEXT STEPS
  • Review Newton's law of gravitation and its application in real-world scenarios.
  • Study the lens equation and magnification formula for convex lenses and mirrors.
  • Practice solving problems involving gravitational field strength at various altitudes.
  • Explore the effects of focal length on image formation in optical systems.
USEFUL FOR

Students preparing for physics exams, educators teaching optics and gravitation, and anyone interested in applying physics concepts to solve practical problems.

ovechkin1313
Messages
1
Reaction score
0

Homework Statement



22. A 5.00 x 10^4 kg shuttle is orbiting the Earth 2.45 x 10^7 m above its surface. What is the Earth's gravitational field strength at this height.
a.)9.80m/s^2 b.) 1.29m/s^2
c.)0.418 m/s^2 d.)0.39m/s^2

23. What is the force of gravity between the shuttle and the Earth in #22
a.)19700 N b.)20900 N c.) 49000 N d.) 64600 N

39. A light bulb 30 cm in front of a convex lens of focal length 20cm. If the light bulb is 5cm high, what is the height of the image?
a.) 5cm b.) 10cm

c.) 15cm d.) 60cm

40. An object is placed 25 cm in front of a convex mirror of focal length 8 cm. Where is the image?
a.) 3.1cm in front of the mirror
b.) 12cm in front of the mirror
c.) 12cm behind the mirror
d.) there is no image

41. a light bulb 30cm in front of a convex lens of focal length 20cm. The image is 60cm from the lens. What is the magnification of the image?
a.) -2
b.) 2
c.)-1/2
d.)1/2

Homework Equations



Added equation sheet.


The Attempt at a Solution



I have no clue on these questions.. I used Fg=G(M) divided by r2
 

Attachments

Physics news on Phys.org
ovechkin1313 said:
I used Fg=G(M) divided by r2
So post what you did.
 
for number 41

Do you know what the Lens Equation and Magnification equation are?
 

Similar threads

  • · Replies 2 ·
Replies
2
Views
1K
Replies
1
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 4 ·
Replies
4
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
3
Views
5K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
9
Views
3K