Physics < Force of Gravity > HELP?

[McKeavey]

During construction of the Canada pavilion in Vancouver, a wrench fell out of a hovering helicopter and took 9.0 s to reach the ground.
How far was the helicopter from the ground?

I'd assume you find Vavg.
And put it into d = v/t
But when I do that I end up with d = 4.9.
The answer says it's 4.0 x 10^2 m AKA 400m.

What did I do wrong?
And there's no additional information given from the Q.

 

[rock.freak667]

You know that y=ut+0.5at².

Assume the initial velocity is zero.

You are given time, what is the height y?

 

[McKeavey]

Oh..
What would be wrong with using d = v/t though?

 

[rock.freak667]

Oh..
What would be wrong with using d = v/t though?

How you plan to go about finding 'v'?

 

[rwisz]

It seems like you have the right approach in calculating the distance using the formula d = v/t. However, the missing piece of information is the initial velocity of the wrench. Without that, it is not possible to accurately calculate the distance.

Additionally, it is important to note that the acceleration of the wrench due to gravity is not a constant 9.8 m/s^2, as it is affected by air resistance and other factors. So, even with the initial velocity, the calculated distance may not be entirely accurate.

In order to accurately determine the distance, we would need to know the initial velocity and also take into account any other factors that may affect the acceleration of the wrench. Without that information, it is not possible to determine the exact distance the helicopter was from the ground.