- #1

b-pipe

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- 0

## Homework Statement

At t=0, a particle is located at x=33m and has a velocity of 19 m/s in the positive X direction. The acceleration of the particle varies with time as shown in the diagram. What is the velocity of the particle at t=3.6s

Diagram:

## Homework Equations

I'm not sure. But I assume its a variation on the equations of motion.

http://en.wikipedia.org/wiki/Equations_of_motion#Equations_of_uniformly_accelerated_linear_motion

## The Attempt at a Solution

Ive gotten the variables:

Initial Position: 33m

Initial Velocity: 19m/s

Initial Time = 0s

Final Time = 3.6 m/s

Acceleration = Unknown

I initially tried to plug the numbers into one of the equations of motion but couldn't come up with an answer. I realized that the equations of motion are only applicable if the acceleration is constant, which the question states it is not. This is where I'm at a loss. I also think that the diagram provides some information on the acceleration but I'm not sure how I'm supposed to get the info from the graph depicted.

Any help would be much appreciated.