Physics problem on power involving escalators

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SUMMARY

The discussion focuses on calculating the power rating required for an escalator that lifts passengers 6 meters in 40 seconds. Given that the escalator must accommodate individuals weighing between 50 to 75 kg, the power can be determined using the equations for work (w = fd) and power (p = w/t). The energy transformation involved includes gravitational potential energy as the passengers are lifted, necessitating a specific power output to maintain the required speed.

PREREQUISITES
  • Understanding of basic physics concepts, specifically work and energy.
  • Familiarity with the equations for work (w = fd) and power (p = w/t).
  • Knowledge of gravitational potential energy calculations.
  • Basic algebra for solving equations.
NEXT STEPS
  • Calculate the gravitational potential energy for a 75 kg person lifted 6 meters.
  • Explore the relationship between power, work, and time in mechanical systems.
  • Investigate the efficiency of escalators and energy losses during operation.
  • Learn about the design considerations for escalators in public spaces.
USEFUL FOR

Students studying physics, engineers involved in mechanical design, and anyone interested in understanding the power requirements of escalators and similar lifting devices.

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Homework Statement



An escalator at a mall lifts passengers 6m. The escalator has to be able to lift 50-75kg people at one time up the lift. The time to make it to the top is 40s. What must the power rating of the escalator be?

Homework Equations


w=fd

p=w/t

The Attempt at a Solution


w=6f
 
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Please show your reasoning and your working.

When people get lifted up by the escalator, some energy changes: what kind?
This energy has to be supplied to the lift - power is the rate of change of energy.
 

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