Piston Question: Have solution, don't understand rationale

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SUMMARY

The discussion centers around a hydraulic chamber problem involving a spring with a spring constant of 1580 N/m, an input piston area of 15.3 cm², and an output plunger area of 66.6 cm². The user calculated the force exerted by a rock of mass 41.9 kg resting on the plunger, resulting in a spring compression of 0.0597 m. The confusion arose from the distinction between the spring force equation (F = kx) and the potential energy stored in a spring (E = 1/2 kx²). The correct application of these formulas is crucial for solving such problems accurately.

PREREQUISITES
  • Understanding of hydraulic systems and pressure transmission
  • Knowledge of spring mechanics, specifically Hooke's Law (F = kx)
  • Familiarity with basic physics concepts such as force, area, and mass
  • Ability to perform unit conversions and area calculations (cm² to m²)
NEXT STEPS
  • Study the principles of hydraulic systems and Pascal's Law
  • Learn more about Hooke's Law and its applications in mechanical systems
  • Explore the relationship between force, area, and pressure in fluid mechanics
  • Review potential energy concepts related to springs and their calculations
USEFUL FOR

This discussion is beneficial for physics students, mechanical engineers, and anyone interested in understanding the mechanics of hydraulic systems and spring dynamics.

hanag
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Homework Statement


The drawing below shows a hydraulic chamber in which a spring (spring constant = 1580 N/m) is attached to the input piston (A1 = 15.3 cm2), and a rock of mass 41.9 kg rests on the output plunger (A2 = 66.6 cm2). The piston and plunger are nearly at the same height, and each has a negligible mass. By how much is the spring compressed from its unstrained position?

Homework Equations



F1/A1=F2/A2
F=kx

The Attempt at a Solution


F1/15.3 cm^2= 410.62 N/66.6 cm^2 F1=94.33 N

94.33 N= 1580 N/m
0.0597 m

I'm pretty sure this is the correct solution, I just don't understand why I should use F=kx rather than F=kx^2.
 
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hanag said:

Homework Statement


The drawing below shows a hydraulic chamber in which a spring (spring constant = 1580 N/m) is attached to the input piston (A1 = 15.3 cm2), and a rock of mass 41.9 kg rests on the output plunger (A2 = 66.6 cm2). The piston and plunger are nearly at the same height, and each has a negligible mass. By how much is the spring compressed from its unstrained position?

Homework Equations



F1/A1=F2/A2
F=kx

The Attempt at a Solution


F1/15.3 cm^2= 410.62 N/66.6 cm^2 F1=94.33 N

94.33 N= 1580 N/m
0.0597 m

I'm pretty sure this is the correct solution, I just don't understand why I should use F=kx rather than F=kx^2.

It looks like you are confusing the equation for spring force (F=-kx) with potential energy stored in a spring (E=1/2kx^2) :-)

http://en.wikipedia.org/wiki/Spring_(device)

http://hyperphysics.phy-astr.gsu.edu/hbase/pespr.html

.
 
Oh, I sure was. Thank you so much!
 

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