Plotting lnη vs 1/T for Water and Alcohol Viscosity Measurements

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AndrejN96
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Homework Statement


Plot the graph of lnη vs 1/T for water (use values from table) and alcohol (values measured previously).
For water:
(Temperature in Kelvin)
T=293.15 η=1.002mPas
T=308.15 η=0.726mPas
T=323.15 η=0.548mPas

For alcohol (measured):
T=293.15 η=3.202
T=308.15 η=1.254
T=323.15 η=0.705

Homework Equations


lnη=(E/R)*(1/T)-lnC

The Attempt at a Solution


I tried just calculating the logarithms of the given values but as expected for values <1 I get negative logarithm values. My question, do I use the negative values as well, or?
 
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