MHB Point on Graph of Equation....2

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The discussion confirms that the point (a - 1, a + 1) lies on the graph of the equation y = x + 2. By substituting x with a - 1, the resulting y value matches the original point's y coordinate, a + 1. The calculations demonstrate that both sides of the equation are equal, validating the point's position on the graph. Thus, it is concluded that the point indeed lies on the graph of the equation. The verification process is accurate and supports the conclusion.
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Determine if the given point lies on the graph of the equation.

(a - 1, a + 1); y = x + 2

Let x = a - 1

Let y = a + 1

y = x + 2

a + 1 = a - 1 + 2

a + 1 = a + 1

Yes, the given point lies on the graph of y = x + 2.

Correct?
 
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Checking:

y = x + 2

Let x = a - 1

y = a - 1 + 2

y = a + 1

After plugging x = a - 1 into the linear equation y = x + 2, I found the original value of y given in the point. So, I conclude that the point (a - 1, a + 1) lies on the graph of the equation.

Correct?
 

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