Point on Graph of Equation....2

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The discussion confirms that the point (a - 1, a + 1) lies on the graph of the equation y = x + 2. By substituting x with (a - 1) in the equation, the resulting y value matches the given point's y-coordinate, validating the conclusion. The mathematical verification process demonstrates that both sides of the equation are equal, affirming the point's position on the graph.

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Determine if the given point lies on the graph of the equation.

(a - 1, a + 1); y = x + 2

Let x = a - 1

Let y = a + 1

y = x + 2

a + 1 = a - 1 + 2

a + 1 = a + 1

Yes, the given point lies on the graph of y = x + 2.

Correct?
 
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Checking:

y = x + 2

Let x = a - 1

y = a - 1 + 2

y = a + 1

After plugging x = a - 1 into the linear equation y = x + 2, I found the original value of y given in the point. So, I conclude that the point (a - 1, a + 1) lies on the graph of the equation.

Correct?
 

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