Population Dynamics: Logistic Model (Differential Equations)

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SUMMARY

The discussion focuses on solving a logistic differential equation related to population dynamics, specifically using the model dp/dt = A P (P1 – P) with a carrying capacity of 100,000 and an initial population of 10,000. The growth rate at t=0 is established at 5%, leading to the need to determine the constant A. Participants clarify that the correct approach involves using the logistic equation rather than the simpler exponential growth model, emphasizing the importance of consistency in variable notation.

PREREQUISITES
  • Understanding of logistic growth models in differential equations
  • Familiarity with the notation and terminology of ODEs (Ordinary Differential Equations)
  • Knowledge of initial value problems and their solutions
  • Basic algebraic manipulation skills for solving equations
NEXT STEPS
  • Study the derivation and solution of the logistic differential equation
  • Learn how to apply initial conditions to solve ODEs
  • Explore the implications of carrying capacity in population models
  • Investigate the differences between logistic and exponential growth models
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Students studying differential equations, mathematicians focusing on population dynamics, and educators teaching mathematical modeling concepts.

KTiaam
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Homework Statement



Population Dynamics: Logistic model. Suppose the environmental carrying capacity of the population is 100000 and the growth rate a t=0 is 5%. . If the population starts at 10000, how long does it take for the population to reach half the carrying capacity?

dp/dt = A P (P1 – P), where P1 = 100 using 1000 as the unit of population. Here P'/P = 0.05 at t = 0.

Use P'/P = 0.05 and the value of P0 given above in the ODE P' = A P (P1 – P) to find A.

You have the solution of the ODE… use it to answer the question.

Homework Equations


dp/dt = A P
p(t) = P0 ekt
dp/dt = A P (P1 – P)

The Attempt at a Solution


P1 = 100
P(0) = 10

From my understanding you want to find P(t) = 50 and t = ?
I'm just having a hard time connecting dp/dt = AP and dp/dt = A P (P1 – P)
do i find what AP is and then set it equal to A P (P1 – P)?

or do i use p(t) = P0 ekt in some way.

It says "you have the solution of the ODE, use it to answer the question"
I am also not understanding what P'/P represents, as it is equal to .05, but that's the answer when i divide 50 by 1000.

Any help is appreciated.
 
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KTiaam said:
dp/dt = A P
p(t) = P0 ekt
dp/dt = A P (P1 – P)
You have conlicting expressions for dP/dt. I believe the second is for the logistic model. The first is for a model that has no limit on carrying capacity.
You need to solve the logistic differential equation.
 
haruspex said:
You have conlicting expressions for dP/dt. I believe the second is for the logistic model. The first is for a model that has no limit on carrying capacity.
You need to solve the logistic differential equation.

Could you explain a little bit more?
So use only p(t) = P0e^kt?
 
KTiaam said:
Could you explain a little bit more?
So use only p(t) = P0e^kt?
No, haruspex was talking about the logistic equation -- dP/dt = AP(P1 - P). This is the one you need to solve for P.

BTW, try to be consistent with the casing of your variables. Don't use dp/dt in one place and P on the other side. P represents population, so the equation should be as I wrote it above.
 
Last edited:
Mark44 said:
No, haruspex was talking about the logistic equation -- dP/dt = AP(P1 - P). This is the one you need to solve for P.
.
Yes, that's what I meant. But I just noticed in the OP it says "you have the solution to the equation". KTiaam, this implies you have already been given the solution to this differential equation, but you have not listed it. Instead, you have listed a simpler ODE and its solution.
 
haruspex said:
But I just noticed in the OP it says "you have the solution to the equation". KTiaam, this implies you have already been given the solution to this differential equation, but you have not listed it.
Yeah, I was wondering about that, and didn't see the solution listed anywhere.
 

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