Position angle of Moon's bright limb (formula)

  • Thread starter JeffOCA
  • Start date
  • #1
49
0

Main Question or Discussion Point

Hi everyone !

I have a question about the position angle of Moon's bright limb.
In "Astronomical Algorithms" (Jean Meeus), one can find the formula to calculate this angle (formula is tagged "46.5"), but there is no explanation about the derivation of this formula.

This is the formula "46.5" :

[tex]tan \chi = \frac{cos \delta_0.sin(\alpha_0 - \alpha)}{sin \delta_0.cos \delta - cos \delta_0.sin \delta.cos(\alpha_0 - \alpha)}[/tex]

where [tex]\alpha[/tex], [tex]\delta[/tex] are the geocentric right ascension and declination of the Moon and
[tex]\alpha_0[/tex], [tex]\delta_0[/tex] are the geocentric right ascension and declination of the Sun.

I think the derivation is maybe explained in the "Practical astronomy with your calculator" (Peter Duffett-Smith) but, unfortunately, I don't have this book at home.

Does anybody can explain the derivation of this formula 46.5 ?

Thanks (... and sorry for my approximative english)
Jeff (from France)
 

Answers and Replies

  • #2
49
0
Of course [tex]\chi[/tex] is the so-called "position angle of the Moon's bright limb"...

Jeff from France
 
  • #3
49
0
No one ?
 
  • #4
tiny-tim
Science Advisor
Homework Helper
25,832
251
Welcome to PF!

Hi Jeff! Welcome to PF! :wink:

Without a diagram, it's difficult to see what's what …

but the denominator is the standard spherical trig formula for cos of the side of a triangle if the other two sides are δ and 90º - δ0, and the opposite angle is α0 - α :smile:
 
  • #5
49
0


Does anyone capable of tracing a diagram of this spherical triangle in order to understqnd the relation given above ?
 

Related Threads on Position angle of Moon's bright limb (formula)

Replies
1
Views
3K
  • Last Post
Replies
0
Views
6K
Replies
6
Views
4K
  • Last Post
Replies
8
Views
5K
Replies
3
Views
9K
  • Last Post
Replies
5
Views
7K
  • Last Post
Replies
12
Views
3K
  • Last Post
Replies
1
Views
3K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
4
Views
2K
Top