arivero
Gold Member
- 3,481
- 187
Just for fun, let me start from the neutron mass and the pion mass.
939.565346 ± 0.000023 MeV
134.9766 ± 0.0006 MeV
We take Koide fundamental mass: 939.565346 / 3=313.188449
(It is also possible to use (2 N - P)/3 = 313.62 )
and for the phase we solve
313.188449 ( 1 + sqrt(2) cos(phase_mu))^2 = 134.9766
which is 1.81615071 o
So
phase_e=1.81615071 + 2*pi/3=3.91054581
phase_tau=1.81615071 - 2*pi/3=-0.278244391=6.00494092
and then mass of electron 0.0833034615 and
mass of tau 1 744.07079
No bad for the tau, but horrible for the electron.
What happens, probably, is that the mass of the pion is not a pure QCD object, it has got mixings and corrections. But perhaps the same could be predicated of the leptonic part. It is interesting to remember that m_e=0 directly "predicts", via phase_e= 3/4 pi, that
m_muon=125 MeV and m_tau=1753 MeV
939.565346 ± 0.000023 MeV
134.9766 ± 0.0006 MeV
We take Koide fundamental mass: 939.565346 / 3=313.188449
(It is also possible to use (2 N - P)/3 = 313.62 )
and for the phase we solve
313.188449 ( 1 + sqrt(2) cos(phase_mu))^2 = 134.9766
which is 1.81615071 o
So
phase_e=1.81615071 + 2*pi/3=3.91054581
phase_tau=1.81615071 - 2*pi/3=-0.278244391=6.00494092
and then mass of electron 0.0833034615 and
mass of tau 1 744.07079
No bad for the tau, but horrible for the electron.
What happens, probably, is that the mass of the pion is not a pure QCD object, it has got mixings and corrections. But perhaps the same could be predicated of the leptonic part. It is interesting to remember that m_e=0 directly "predicts", via phase_e= 3/4 pi, that
m_muon=125 MeV and m_tau=1753 MeV
