Potential Grav. Energy to Kine. Energy Problem

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SUMMARY

The discussion focuses on calculating the energy lost due to friction on a roller coaster ride, specifically between two peaks, K and L. The total mass of the cart is 280 kg, with peak K at 46.0 m and peak L at 21.5 m. The kinetic energy (KE) at peak K is calculated using the formula KE = 1/2mv², resulting in a value of 85000 J when comparing the total energy (KE + PE) at both points. The confusion arose from the initial attempts to calculate energy loss using incorrect methods.

PREREQUISITES
  • Understanding of kinetic energy (KE) and potential energy (PE) equations
  • Familiarity with gravitational potential energy calculations
  • Basic knowledge of roller coaster physics
  • Ability to perform unit conversions and calculations involving mass and height
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  • Study the principles of energy conservation in mechanical systems
  • Learn about the effects of friction on energy loss in roller coasters
  • Explore advanced calculations involving potential and kinetic energy in varying heights
  • Investigate real-world applications of energy loss calculations in engineering
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Physics students, engineering students, and anyone interested in understanding energy dynamics in mechanical systems such as roller coasters.

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Homework Statement


On a roller coaster ride the total mass of the cart - with passengers included - is 280 kg. Peak K is at 46.0 m above the ground, peak L is at 21.5 m. The speed of the cart at K is 17.1 m/s, at L it is 12.8 m/s. How much energy is lost due to friction between the two peaks?


Homework Equations


Ke = 1/2mv^2 = mgh


The Attempt at a Solution


I tried finding the Ke at the 2 different points and subtracting.. it didn't work .
then i tried with the mgh and subtracted it, and it still didn't work.
So i guess I'm confused on which of the given data i should use.

Thanks a lot!
 
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Compare the total energy (KE + PE) at the two points.
 
i see. I got 85000, which was right.
Thanks again
 

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