Potentiometer Problem: 3V Battery, 100cm Sliding Wire, and 60cm Voltmeter

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SUMMARY

The discussion centers on calculating the voltmeter reading in a circuit involving a 3V battery with an internal resistance of 1Ω, a 100 cm sliding wire with a resistance of 5Ω, and a voltmeter connected across a 60 cm segment of the wire. The calculated reading of the voltmeter is 1.5 volts when the voltmeter has negligible current draw. Additionally, the discussion explores the scenario where the voltmeter has a resistance of 150Ω, prompting further analysis of the circuit configuration.

PREREQUISITES
  • Understanding of Ohm's Law (V=IR)
  • Familiarity with series and parallel resistor configurations
  • Basic knowledge of circuit analysis techniques
  • Concept of internal resistance in batteries
NEXT STEPS
  • Research the impact of voltmeter resistance on circuit readings
  • Learn about circuit simplification techniques using lumped resistors
  • Study the effects of internal resistance in battery-powered circuits
  • Explore advanced circuit analysis methods, such as Thevenin's theorem
USEFUL FOR

Students studying electrical engineering, hobbyists working with circuits, and anyone interested in understanding the behavior of voltmeters in practical applications.

kaka01
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Homework Statement


A 3-V battery of internal resistance 1Ω is joined to a sliding wire of length 100 cm and resistance 5 Ω . A voltmeter , which takes negligible current , is connected across 60 cm length of the wire . (a) What is the reading of the voltmeter ? (b) If the reistance of the voltmeter were 150 Ω , then what would have been its reading ?

Homework Equations


I=E/(R+r)

The Attempt at a Solution



I=E/(R+r)

V=IR

V=0.5 x 5

=2.5

K=.025

Reading= .025x60=1.5 volt

I am not getting second part .
[/B]
 
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What have you tried? Have you drawn the circuit? Can you post it?
 
Well split the wire into two parts (60 cm and 40 cm) and convert the circuit into lumped resistors..It'll get simple..
 

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