Power series in quantum mechanics

Click For Summary
SUMMARY

The discussion focuses on the application of the power series method to solve ordinary differential equations (ODEs) in the context of the infinite square well in quantum mechanics. The user derived the wave function as $$\psi(x) = \sum^{\infty}_{n=0} k^{2n}(\cos(x) + \sin(x))$$, where ##k = \frac{\sqrt{2mE}}{\hbar}##. However, the user identified a flaw in their approach, noting that the solution does not yield quantized energy levels due to the lack of consideration for boundary conditions essential for the infinite square well problem.

PREREQUISITES
  • Understanding of ordinary differential equations (ODEs)
  • Familiarity with quantum mechanics concepts, specifically the infinite square well
  • Knowledge of boundary conditions in quantum systems
  • Basic proficiency in series solutions and power series methods
NEXT STEPS
  • Study the derivation of wave functions in the infinite square well using boundary conditions
  • Learn about quantization of energy levels in quantum mechanics
  • Explore the application of power series methods in solving differential equations
  • Investigate the role of boundary conditions in determining physical solutions in quantum systems
USEFUL FOR

Students and professionals in physics, particularly those studying quantum mechanics, as well as educators seeking to clarify the application of power series methods in solving quantum systems.

gremory
Messages
3
Reaction score
0
TL;DR
Power series to solving the infinite square well
Just earlier today i was practicing solving some ODEs with the power series method and when i did it to the infinite square well i noticed that my final answer for ##\psi(x)## wouldn't give me the quantised energies. My solution was
$$\psi(x) = \sum^{\infty}_{n=0} k^{2n}(\cos(x) + \sin(x))$$, with ##k = \frac{\sqrt{2mE}}{\hbar}##. I want to know what's the catch when doing this because we need the boundary conditions to quantize the energies and with this solution i don't see how i would get that.
 
Last edited:
Physics news on Phys.org
\psi(x) = \sum^{\infty}_{n=0} k^{2n}(\cos(x) + \sin(x))=(\cos(x) + \sin(x)) \sum^{\infty}_{n=0} k^{2n}=\psi(x,k)

so something seems wrong. Where are the edges of infinite well ?
 
Last edited:

Similar threads

  • · Replies 21 ·
Replies
21
Views
3K
  • · Replies 6 ·
Replies
6
Views
3K
  • · Replies 27 ·
Replies
27
Views
3K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 22 ·
Replies
22
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 12 ·
Replies
12
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K