Powers of p and q from a=v^p*t^q

  • #1
How do I go about solving for the powers of p and q to make the equation dimensionally consistent?

Any help or advice would be much appreciated! :smile:
 

Answers and Replies

  • #2
538
148
I'm assuming v is velocity, t is time and a is acceleration?

Acceleration has units of m/s2, while velocity has units of m/s. So the only valid values of p and q would have to be p = 1 and q = -1.
 
  • #3
I'm assuming v is velocity, t is time and a is acceleration?

Acceleration has units of m/s2, while velocity has units of m/s. So the only valid values of p and q would have to be p = 1 and q = -1.
Yes, I failed to mention that. Thank you for your help. :smile:
 

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