What products are expected in the electrolysis of CuBr2(aq)?
The Attempt at a Solution
This is actually a solved example from my textbook that I have a question about. It says to first consider the possible reactions at the cathode.
Since reduction happens at the cathode, it says the possible reductions are:
Cu2+(aq) + 2e- --> Cu(s) E = +0.34
2H2O(l) + 2e- --> H2(g) + 2OH- E= -0.83
The first one happens because its E is the most positive.
What I'm wondering is why we didn't include the reduction of Br2. Is it because Br- is an anion that we don't consider it?
And, how did they know to use the reaction for water that I gave and not 2H20(l) --> O2(g) + 4H+ + 4e-? (Because it's oxidation, which can't happen at the cathode, right?)