Prepare 1.00L 0.50M NiCl2 from NiCl2*6H2O

[disneychannel]

How would you prepare 1.00 L of 0.50M solution sof NiCl₂ from the salt NiCl₂ * 6H₂O

 

[symbolipoint]

The initial target is the number of MOLES of NiCl₂. The moles you use of dry hydrated NiCl₂ and the moles of the anhydrous NiCl₂ would be identical. In the task you will actually weigh the hydrated compound. First determine formula weight of the sexa-hydrate.