MHB Probability of Order Accuracy from A, C, or Not Accurate

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The discussion focuses on calculating the probability of selecting an order from restaurant A, C, or an inaccurate order. The relevant data shows the number of accurate and inaccurate orders for each restaurant. The correct setup for the probability calculation involves using the addition rule for probabilities. The formula used combines the totals from A and C, as well as the inaccurate orders from B and D, divided by the overall total of orders. The computed probability is approximately 0.633.
jridgeman99
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This is a problem I got for a review in probability and statistics

The layout of the data is as follows:
A B C D
Order Accurate- 315 277 234 120
Order not - 34 50 35 18
accurate

Like I said previously this is an or problem and this means it is an addition rule problem. The problem wants me to compute
the probability that whenever a single order is selected what is the probability that this probability is from restaurant A or C or an order that is not accurate.
I know the answer is .633 I just can't figure out how to set up the problem.
 
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jridgeman99 said:
This is a problem I got for a review in probability and statistics

The layout of the data is as follows:
A B C D
Order Accurate- 315 277 234 120
Order not - 34 50 35 18
accurate

Like I said previously this is an or problem and this means it is an addition rule problem. The problem wants me to compute
the probability that whenever a single order is selected what is the probability that this probability is from restaurant A or C or an order that is not accurate.
I know the answer is .633 I just can't figure out how to set up the problem.

[(all A) + (all C) + (inaccurate B) + (inaccurate D)]/total

$\dfrac{(315+34)+(234+35)+50+18}{1083} = 0.6334$
 
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