MHB Probability of Order Accuracy from A, C, or Not Accurate

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SUMMARY

The discussion focuses on calculating the probability of order accuracy from restaurants A and C, or orders that are not accurate, using the addition rule in probability. The data provided includes accurate and inaccurate orders from four restaurants, with specific counts: A (315 accurate, 34 not), B (277 accurate, 50 not), C (234 accurate, 35 not), and D (120 accurate, 18 not). The correct probability calculation yields a result of approximately 0.633, derived from the formula: [(all A) + (all C) + (inaccurate B) + (inaccurate D)]/total.

PREREQUISITES
  • Understanding of basic probability concepts, specifically the addition rule.
  • Familiarity with data representation in contingency tables.
  • Ability to perform arithmetic operations with fractions and totals.
  • Knowledge of how to interpret statistical results in context.
NEXT STEPS
  • Study the addition rule of probability in detail.
  • Learn how to construct and analyze contingency tables.
  • Explore examples of probability calculations involving multiple events.
  • Practice with real-world scenarios to apply probability concepts effectively.
USEFUL FOR

This discussion is beneficial for students studying probability and statistics, educators teaching these concepts, and anyone involved in data analysis requiring accurate probability calculations.

jridgeman99
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This is a problem I got for a review in probability and statistics

The layout of the data is as follows:
A B C D
Order Accurate- 315 277 234 120
Order not - 34 50 35 18
accurate

Like I said previously this is an or problem and this means it is an addition rule problem. The problem wants me to compute
the probability that whenever a single order is selected what is the probability that this probability is from restaurant A or C or an order that is not accurate.
I know the answer is .633 I just can't figure out how to set up the problem.
 
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jridgeman99 said:
This is a problem I got for a review in probability and statistics

The layout of the data is as follows:
A B C D
Order Accurate- 315 277 234 120
Order not - 34 50 35 18
accurate

Like I said previously this is an or problem and this means it is an addition rule problem. The problem wants me to compute
the probability that whenever a single order is selected what is the probability that this probability is from restaurant A or C or an order that is not accurate.
I know the answer is .633 I just can't figure out how to set up the problem.

[(all A) + (all C) + (inaccurate B) + (inaccurate D)]/total

$\dfrac{(315+34)+(234+35)+50+18}{1083} = 0.6334$
 

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