Probability: Permutations/Combinations

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The discussion focuses on calculating probabilities related to permutations and combinations in a scenario with 4 sections and 3 students selecting sections at random. The sample space S is determined to be 64, as each student has 4 choices (4^3 = 64). The probability that all students end up in the same section is calculated as 3/64, while the probability that all students choose different sections is 6/64. Additionally, the probability that no student selects section 1 is derived as 6/64. The discussion also suggests extending these calculations to a general case with n sections and s students.

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catbearbig
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I'm having a hard time understanding how to derive the # ways to do things.

(a) A course has 4 sections with no limit on how many can enrol in each section. 3 students each pick a section at random.

(i) Specify Sample Space S (64?)
(ii)Find the probability that they all end up in the same section (3C1 /64 = 3/64??)
(iii) Find the probability that they all end up in different sections (3P3/64 = 6/64 ??)
(iv) Find the probability that nobody picks section 1 ( 3C2 * 2! / 64 = 6/64??)

(b) Repeat (a) in the case where there are n sections and s students.

Can someone please help me derive their answers of how they get the # of ways to do each. Thanks a lot!
 
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I suggest, first, that you check the top thread on how to present a homework problem. Or look at the standard layout used by most others.

For your probability answer, don't forget there are 4 sections, not 3. And a little more explanation of your thinking would help others to help you.
 

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