Probability Prob,Given P(A)=0.5, P(A U B)=0.8 and P(A ∩ B)=0.1. Find P(A/B).

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SUMMARY

The problem involves calculating the conditional probability P(A/B) given P(A)=0.5, P(A U B)=0.8, and P(A ∩ B)=0.1. Using the equation P(A U B) = P(A) + P(B) - P(A ∩ B), the value of P(B) is determined to be 0.4. Subsequently, applying the formula P(A/B) = P(A ∩ B) / P(B), the final result is calculated as 0.25. The methodology and calculations presented are confirmed to be accurate.

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Homework Statement


Given P(A)=0.5, P(A U B)=0.8 and P(A ∩ B)=0.1. Find P(A/B).

Homework Equations


EQ 1: P(A U B) = P(A) + P(B) - P(A ∩ B)
EQ 2: P(x/y)= P(A ∩ B) divided by P(B)

The Attempt at a Solution


Immediately my first thought is to solve for P(y). So using EQ 1, I solve for P(B) by plugging the variables in, which resulted in 0.4. Is this right so far?
Once I did this I just used EQ 2, dividing 0.1/0.4 to get 0.25, which was my answer.
 
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I did not check your numbers, but your method is correct.
 
thank you! that's all I wanted to know :)
 

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